Subject: RE: [xsl] document() and xpath From: "Dion Houston" <dionh@xxxxxxxxxxxxx> Date: Mon, 29 Apr 2002 12:03:58 -0700 |
You should be able to do (before your for-each): <xsl:variable name="formNodes" select="/page/form"/> And then replace apply-templates with: <xsl:apply-templates select="$formNodes"/> You probably should consider restructuring your XSL so you don't have to create a temp variable... maybe something like... (?) <xsl:apply-templates select="document('xml.xml')/menu/name | /page/form"/> And then have templates for name and form. HTH! Dion -----Original Message----- From: Meltem Kogelbauer [mailto:meltem.kogelbauer@xxxxxxxxxxxxxxxx] Sent: Monday, April 29, 2002 11:39 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] document() and xpath Hi All, here is the simplified version of code; 1st XML that is generated on-the-fly <page> <form> <name/> <id/> </form> ... </page> 2nd XML that is a flat file, xml.xml <menu> <name/> <name/> <name/> </menu> In the XSL <for-each select="document('xml.xml')/menu/name"> <value-of select="text()"/> <apply-templates select="/page/form" /> </for-each> My problem is with the xpath (I think) in <apply-templates> element. When looping in the external XML, how can I write the XPath to the current document? Is this possible? cheers Meltem XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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