Subject: [xsl] Processing formatted XML? From: "Robert Nicholson" <robert@xxxxxxxxxxxx> Date: Wed, 1 May 2002 17:57:22 -0700 |
Can anybody give me any points as to how to process formatted, for the sake of readability, and generate readable ascii Text? Specifically I want to know what the stylesheet should do maintain format but at the same time remove leading and trailing spaces. I have two rules <xsl:template match="notes"> <xsl:call-template name="separated-list"> <xsl:with-param name="nodes" select="note"/> <xsl:with-param name="separator"> </xsl:with-param> </xsl:call-template> </xsl:template> <xsl:template name="separated-list"> <xsl:param name="nodes"/> <xsl:param name="separator"/> <xsl:for-each select="$nodes"> <xsl:copy-of select="."/> <xsl:if test="position() != last()"> <xsl:copy-of select="$separator"/> </xsl:if> </xsl:for-each> </xsl:template> The source XML looks like this ie. There are line breaks in the original source. And ideally I want to capture those line breaks when generating the output but I do not want to capture all the leading white spaces that effectively represent formatting ie. Indentation to keep the XML readable. So as the stylesheet writer? Is it my obligation to strip away those leading spaces? Ie. All spaces before Please, green, This, with, I, require. <notes> <note> Please note that I am a British and Australian citizen who is a green card holder as of 12th May, 1999. </note> <note> Also, email is my preferred method of correspondence. </note> <note> This resume is stored in XML and converted to HTML via XSLT with the Michael Kay's Saxon XSL Processor. </note> <note> I am prepared to relocate for the right position and I do not necessarily require relocation assistance. </note> </notes> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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