RE: [xsl] Can't Obtain Results

Subject: RE: [xsl] Can't Obtain Results
From: "Lindy Quick" <lindyq@xxxxxxxx>
Date: Fri, 3 May 2002 09:58:42 -0400 (EDT)

Your Solution worked while I know that I will only have these vaules in the immediate future.  Thank you.  Also good idea on the email format, but you can see below it doesn't work.  I have notified my provider.


You are correct in your second assumption that I am looking for the values that are not in the second set.
I am interested in pursuing this farther, and will spend most of today working with Keys and groups.
I am however limited to using the XSLT 1.0.

While I see the ease of using 2.0, I am stumped how to create that in 1.0 Can anyone help?


MK Wrote:
> What's special about f1 and f6? Is it that they are the first and last
> elements in the first keyset, or is it that they are the only ones not
> present in the second keyset? (Sometimes reverse engineering the
> algorithm
> from an example of its output isn't easy...)
> Let's assume the latter. In this case you have an
> elimination-of-duplicates
> problem, which is essentially the same as a grouping problem. The
> grouping
> key (the thing that's the same between matching elements) is the element
> name rather than it's value, so you can't use the simple
> *[not(.=preceding::*)] technique; instead you need to use keys.
> Look up Muenchian grouping in your favourite textbook or at
>, and use it with a grouping key
> declared
> as
> &lt;xsl:key name="g" match="keyset/*"
> use="name()"/>
> Or if you want to use XSLT 2.0, as implemented in Saxon 7.1, you can
> write
> &lt;xsl:for-each-group select="(keyset[1] |
> keyset[@outlet=$outlet])/*"
>  group-by = "name()">
>    &lt;xsl:copy-of select="."/>
> &lt;/xsl:for-each-group>

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