|
Subject: Re: [xsl] data translation => descendants appear side by side in HTML-table From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Sat, 04 May 2002 15:25:18 +0200 |
<xsl:template match="description">
<xsl:variable name="pos" select="position()"/>
<tr>
<xsl:for-each select="/root/base">
<td>
<xsl:value-of select="(.//description)[$pos]"/>
</td>
</xsl:for-each>
</tr>
</xsl:template>should be transformed into:
<table> <tr> <td>some_desc1</td> <td>some_desc1</td> </tr> <tr> <td>some_desc2</td> <td>some_add_desc2</td> </tr> <tr> <td>some_add_desc3</td> <td>some_desc3</td> </tr> <tr> <td>some_add_desc4</td> <td>some_desc4</td> </tr> <tr> <td></td> <td>some_add_desc5</td> </tr> </table>
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| Re: [xsl] xpath - how to return all, G. Ken Holman | Thread | Re: [xsl] data translation => desce, Wendell Piez |
| Re: [xsl] data translation => desce, Joerg Heinicke | Date | RE: [xsl] passing intermediate resu, Michael Kay |
| Month |