RE: [xsl] Namespaces in XSLT

Subject: RE: [xsl] Namespaces in XSLT
From: "Evan Lenz" <evan@xxxxxxxxxxxx>
Date: Sat, 4 May 2002 19:51:07 -0700
tinku wrote:
>    Is the default namespaces taken into account when processing
> XPATHs in an XSL stylesheet? What will be generated as the
> following is given:

I think you might be asking two different questions here:

1) Is the default namespace taken into account when evaluating XPath
expressions (or match patterns) in an XSLT stylesheet?

2) Is the default namespace taken into account when creating an element with
a literal result element?

The answer to #1 is no. Looking at your example:

> <xsl:template xmlns= ""; match='bo[@xpath]'>
>        <foo/>
> </xsl:template>

This template rule will only match "bo" elements that are not in a
namespace. If you want to match (or select) "bo" elements in a namespace,
you must use a prefix and corresponding xmlns declaration.

Note that, for the sake of convenience, XSLT 2.0 will provide a way to
declare a default namespace for XPath expressions and XSLT patterns, in the
form of an [xsl:]default-xpath-namespace attribute. See

The answer to #2 is yes. More accurately, the XSLT processor just takes the
local/URI pair that the namespace-aware XML parser gives to it. In your
example above, the <foo/> element name consists of the following local/URI
pair: ("foo", "";). That is the name given to the created
element in the result tree.

Hope this helps,

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