Re: [xsl] Pass-Through of MathML-Elements

Subject: Re: [xsl] Pass-Through of MathML-Elements
From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>
Date: Tue, 14 May 2002 11:36:11 +0100
Hi Maik,

> I thought the default rule for XSLT processors is to pass the output
> through so I deleted the whole Formula template - same result. What
> output parameter, encoding or template do I need to define to get
> MathML elements pass through?

The default behaviour, if you don't have templates for elements, is to
get their *text content*. This is exactly the same as getting their
string value -- all of their text descendants concatenated together --
which is what you get when you use xsl:value-of.

You should be using xsl:copy-of to copy the structure. Try:

<xsl:template match="Formula">
    <xsl:when test="@Display='Block'">
        <xsl:copy-of select="node()"/>
      <xsl:copy-of select="node()"/>



Jeni Tennison

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