Re: [xsl] How can a template match elements created by xsl?????

Subject: Re: [xsl] How can a template match elements created by xsl?????
From: ChivaBaba@xxxxxxx
Date: Thu, 16 May 2002 05:12:44 EDT
J.Pietschmann wrote:

>If this still doesn't fix your problem, check whether
> you have set a default namespace for the style sheet.

You was right again, it was a namespace-problem. as you see, I defined a default namespace:

<xsl:stylesheet version="1.1"

Following your advice to check the variable with copy-of I realized that 'tool' belongs to the "html"-namespace.

I fixed the problem by creating " <tool xmlns=""> "  instead of " <tool> " and now the template matches what I want. 

But by checking the output I get now, I realized that the double sort you sent me some mails ago does not work right.


 <xsl:variable name="sw">
     <xsl:for-each select="exsl:node-set($tools)">
      <xsl:sort data-type="text" lang="en" select="@category"/>
      <xsl:sort data-type="text" lang="en" select="@name"/>
      <xsl:copy-of select="."/>


My tools in $tools are only sorted by category but not by name!!
What could the problem with this sort-instruction be????

Many Thanks and much respect,


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