Re: [xsl] Adjusting sorted list

[Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>]

Andrew Timberlake wrote:
> I have the following XML:
> <a>
>     <b>4</b>
>     <b>9</b>
>     <b>6</b>
>     <b>1</b>
>     <b>8</b>
>     <b>6</b>
>     <b>4</b>
>     <b>7</b>
> </a>
>
> I am trying to generate the following ouput:
> <a>
>     <b rank="1">1</b>
>     <b rank="2">4</b>
>     <b rank="2">4</b>
>     <b rank="3">6</b>
>     <b rank="3">6</b>
>     <b rank="4">7</b>
>     <b rank="5">8</b>
>     <b rank="6">9</b>
> </a>

For interest, the XSLT 2.0 version would be:

<xsl:template match="a">
  <a>
    <xsl:for-each-group select="b" group-by="." />
      <xsl:sort select="." />
      <xsl:variable name="rank" select="position()" />
      <xsl:for-each select="current-group()">
        <b rank="{$rank}">
          <xsl:value-of select="." />
        </b>
      </xsl:for-each>
    </xsl:for-each-group>
  </a>
</xsl:template>

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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