Subject: Re: [xsl] accessing last element of node set passed as parameter|
From: "J.Pietschmann" <j3322ptm@xxxxxxxx>
Date: Mon, 20 May 2002 23:44:17 +0200
I'm trying to figure out how to access the last element> of a node set which is passed as a parameter to a template.
For example, with:
<xsl:template match="FOO"> <xsl:param name="result" select="/.." /> <xsl:variable name="prior" select="$result/BAR[last()]" /> <!-- Something done it is --> </xsl:template>
if "FOO" is matched, and the parameter, "result", is assigned the node set
<BAR i=1/><BAR i=2/><BAR i=3/>
what expression would I need to access the last "BAR" element
You are trying to select the last of BAR *children* of anything in the passed node set. Try select="$result[last()]", though I'm not sure it'll work either.