Re: [xsl] accessing last element of node set passed as parameter

["paul morgan" <pmorg@xxxxxxxxx>]

Thanks David!  Some of this is starting to click ... but then again something happens that shuts the clicker down.

Since order is important to me, I decided to heed your warning about the ordering of a union being implementation dependent, so I set about making all of the "BAR" elements be siblings of one another.  I replaced:

    <xsl:apply-templates select="following-sibling::*[1]">
        <xsl:with-param name="result" select="$result|xalan:nodeset($new)"/>
    </xsl:apply-templates> </xsl:template> 

with:

    <xsl:apply-templates select="following-sibling::*[1]">
        <xsl:with-param name="result">
            <xsl:copy-of select="$result"/>
            <BAR i="{$i}"/>
        </xsl:with-param>
    </xsl:apply-templates> </xsl:template> 

but now I get the following error message:

    Can not convert #RTREEFRAG to a NodeList!

at the line:

    <xsl:copy-of select="($result/BAR)[last()]" />

the first time the "A" template is matched with a non-empty value for "result".  Shouldn't "result" be a node set?

Paul (I think this language is going to make my head explode)
 
--

On Tue, 21 May 2002 18:09:50  
 David Carlisle wrote:
>
>
>     produce identical output given the input:
>      <IN><A/><A/><A/><A/><A/><A/></IN>
>
>   Below is a transform in which the two lines:
>
>    <xsl:copy-of select="($result/BAR)[last()]" />
>    <xsl:copy-of select="$result[last()]" />
>
>
> "$result|xalan:nodeset($new)"/>
>
>Ha! I guessed two possible meanings:
>
>
>
>> But they can not have done. If $result holds a root node then
>> $result/BAR
>> selects all the BAR children of that node and
>> ($result/BAR)[last()]
>> selects the last of those children.
>> 
>> But if $result contains three BAR nodes then
>> 
>> $result/BAR
>> 
>> selects all the BAR children of each element of $result, and that is
>> empty so ($result/BAR)[last()] is similarly empty.
>> 
>>  
>
>But in fact you have a third.
>
>$result in this case contains three _root_ nodes so $result does have
>three nodes, so <xsl:copy-of select="($result/BAR)[last()]" does pick
>out the last. But they are root nodes not BAR nodes so
>"($result/BAR)[last()]" gives you the last BAR.
>Since copy-of throws away root nodes and just gives you thier contents,
>you do get the same.
>
>Note however that it is undefined which one you get, you are taking the
>union of a new root node with a set of existing root nodes. Root nodes
>are in an implementation defined order so you can not be sure that the
>last one you added is the one you get with last().
>
>If the order matters you need to make sure your bar elements are
>siblings of each other, then the result variable will have a single root
>node containing the elements that you are interested in.
>
>David
>
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