Subject: Re: [xsl] passing parameter to template From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 29 May 2002 15:51:34 +0100 |
> <xsl:apply-templates select="exsl:node-set($tools)"> that applies templates to the root node, so you either need to have a template for / that handles the parameter or you need to do <xsl:apply-templates select="exsl:node-set($tools)/*"> ^^ so you pass apply templates to the first element, so if that is <tool> the template you showed would have the param. > <xsl:with-param name="sort"> > <xsl:value-of select="$sort_dir"/> > </xsl:with-param> Unless you particularly want to create a result tree fragment here (which is unlikely) you would be much better off doing <xsl:with-param name="sort" select="$sort_dir"/> David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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