RE: [xsl] problem with last() function

["Michael Kay" <michael.h.kay@xxxxxxxxxxxx>]

self::node()[position()=last()] is exactly analogous to
child::node()[position()=last()] - it finds all the nodes on the self
axis and from these, selects the last one.

instead of "| self::node()[position()=last()]", write "or
position()=last()". Alternatively, write "or
not(following-sibling::node())" - which is less dependent on how your
template happens to be called, and may be cheaper to evaluate.

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> John Walker
> Sent: 30 May 2002 15:05
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] problem with last() function
> 
> 
> Hi All!
> 
>     I want to know if a node is followed by some particular 
> nodes or if 
> it's the last node of the set. So I've tried:
> 
>             <xsl:if test="following-sibling::table | 
> following-sibling:list | self::node()[position()=last()]">
> 
> I've had to use "self::node()[position()=last()]" instead of simply 
> "position()=last()" because this last comparison doesn't return a DOM 
> node (wich seems to enter in conflict with the previous 
> comparisons)... 
> but it doesn't work! "self::node()[position()=last()]" always returns 
> the current node, doesn't matter if it's the last or not.
> I've an alternative solution, but I'd like to know why this 
> particular 
> expresion doesn't work! (...despite of curiosity killed the cat...)
> 
> Thanx a lot!
> 
> 
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