Re: [xsl] Elements of non-actual position

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

<xsl:template match="table/rows">
  <xsl:for-each select="row">
    <xsl:variable name="pos" select="position()"/>
    <xsl:if test="/table/cols/col[$pos]/@visible = '1'">
      do what you want
    </xsl:if>
  </xsl:for-each>
</xsl:template>

Regards,

Joerg

Rudolf Pischek wrote:
> Hi, 
> I have a problem of searching in my XML data:
> <table>
>   <cols>
>     <col visible="1"/>
>     <col visible="1"/>
>     <col visible="1"/>
>     <col visible="0"/>
>     <col visible="1"/>
>     <col visible="1"/>
>     <col visible="0"/>
>   </cols>
>   <rows>
>     <row>
>       <cell>1</cell>
>       <cell>2</cell>
>       <cell>3</cell>
>       <cell>4</cell>
>       <cell>5</cell>
>       <cell>6</cell>
>       <cell>7</cell>
>     </row>
>     <row>
>       ...
>     </row>
>     ...
>   </rows>
> </table>
>
> and if I have a template:
>
> <xsl:template match="table/rows">
>   <!-- and I want in for-each: Give me all elements cell which position is the same as the position of elements cols which attribute visible is 1 -->
>   <xsl:for-each="...">
>     <!-- than this for-each must contain: cell 1, cell 2, cell 3, cell 5, cell 6 -->
>
>   </xsl:for-each>
> </xsl:template>
>
> I have no idea how I can get elements, one element I can...
> Thanks very much
> Rudolf


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