Re: [xsl] Pass an element based on its childrens content

[Mike Brown <mike@xxxxxxxx>]

CROFT, MICHAEL wrote:
> I need to pass an element to a template based on a condition where its
> children would contain certain text(an id).  

<xsl:param name="cid"/>  <!-- $cid comes from somewhere.. it is either a
                              string or a node-set containing the claim
                              IDs to find. it doesn't have to be a param -->

<!-- template to process the root node (always the first node processed) -->
<xsl:template match="/">
  <!-- go process the matching InsClaimElements elements, one at a time -->
  <xsl:apply-templates select="ListOfInsClaimsElements/InsClaimsElements[ClaimId=$cid]"/>
</xsl:template>

<!-- template to process an InsClaimsElements element -->
<xsl:template match="InsClaimsElements">
  <result>
    <xsl:text>The claim ID is </xsl:text>
    <xsl:value-of select="ClaimId"/>
    <xsl:text>and the claimant is </xsl:text>
    <xsl:value-of select="concat(ClaimantFirstName,' ',Claimant,'.')"/>
  </result>
</xsl:template>

> I need to find the list of claims elements (ListOfInsClaimsElements) which
> contains the claims (InsClaimsElements) that Im interested in (ClaimId).

The above will work even if $cid is a node-set.

> THen I would pass this entire list to a called template for processing.

The way XSLT works, you generally just select nodes for processing
with xsl:apply-templates or xsl:for-each. Select the right nodes, and
have a template to match them. You don't need to pass node-sets as
parameters to named templates.

> THere are multiple lists within the xml document each with possible multiple
> claims but each list of claims only belongs to one claimant.

See the FAQ at www.dpawson.co.uk for more sorting and grouping examples.

   - Mike
____________________________________________________________________________
  mike j. brown                   |  xml/xslt: http://skew.org/xml/
  denver/boulder, colorado, usa   |  resume: http://skew.org/~mike/resume/

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