Re: [xsl] Identity Transform and Default Templates, I think...

[David Carlisle <davidc@xxxxxxxxx>]

  As far as I know, these two are equivalent:

  in full:
    <node>
      <xsl:attribute name="id">
      <xsl:value-of select="node"/>
      </xsl:attribute>
     </node>

  avt:
    <node id="{node}"/>
    

oops yes I was thinking about the version i gave in my reply not this
version, sorry.
The only way around producing id="" (if node is empty/not there) is to
use:

     <node>
       <xsl:if test="node">
       <xsl:attribute name="id">
          <xsl:value-of select="node"/>
         </xsl:attribute>
       </xsl:if>
     </node>


Or simpler in the case of just copying, which is what i gave in my first
reply and was thinking about when I gave the incorrect response above:

<node>
  <xsl:copy-of select="@id"/>
</node>


David

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