Subject: Re: [xsl] Finding out the existence of a node From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx> Date: Mon, 01 Jul 2002 14:10:44 +0200 |
What about <xsl:if test="document($source)/descendant::*[local-name()=$node_name]">
Hi,
is there a way to find out if a particular node exists in an xml file or not?
For example, I have an xml file which has a node <MyName>, how can I know if the same node is also present in another xml file which the stylesheet is processing?
<xsl:variable name="node_name" select="local-name()"/> gives me the name of the node into the variable node_name.
<xsl:param name="source" select="./Doc.xml"/> gives selects the path of Doc.xml into $source
Now how do I know whether $node_name is present in Doc.xml or not? Please help me out.
Thanks,
Kalyan _________________________________________________________ There is always a better job for you at Monsterindia.com. Go now http://monsterindia.com/rediffin/
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