Re: Re: [xsl] Re: WML input problem

Subject: Re: Re: [xsl] Re: WML input problem
From: "ashu t" <aashut@xxxxxxxxxxxxxx>
Date: 8 Jul 2002 14:31:58 -0000
thanks a lot
i tried that code but some how it is not working the whole template match code is
<xsl:template match="//input">
<xsl:variable name="type" select="@type"/>
<xsl:if test="$type='text' or $type='password' or $type='radio' or $type='checkbox'">
<xsl:choose>
<xsl:when test="$type='text'">
<input name="{@name}" type="{@type}">
<xsl:apply-templates/>
</input>
</xsl:when>
<xsl:when test="$type='password'">
<input name="{@name}" type="{@type}">
<xsl:apply-templates/>
</input>
</xsl:when>
<xsl:when test="$type='radio' and generate-id()=generate-id(key('radios',@name))">
<select name="{@name}">
<xsl:for-each select="key('radios', @name)"/>
<option value="{@value}">
<xsl:apply-templates/>
</option>
</xsl:for-each>
</select>
</xsl:when>
</xsl:choose>
</xsl:if>
</xsl:template>


and i have declared <xsl:key>at top at this place just after <xsl:stylesheet>
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:key name="radios" match="input[@type='radio']" use="@name"/>
<xsl:output omit-xml-declaration="yes"/>


but it is not working but if i remove the when condition for input type=radio it is working fine for rest of two input types.what can be the reason and one more thing i did not get the need for<<and generate-id()=generate-id(key('radios',@name))>>
ashu
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