Subject: [xsl] xsl:variable with expr From: "sanghamitra das" <sanghamitra.das@xxxxxxxxxx> Date: Tue, 9 Jul 2002 09:57:38 +0530 |
Hi , I am not able to run the following code it gives an error saying XSLT Error (javax.xml.transform.TransformerConfigurationException): "expr" xsl:variable element! Can anu tell me the reason. sanghamitra <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xslt" > <xsl:template match="/"> <xsl:variable name="DebugOpts" expr="abc123"/> <xsl:call-template name="childTemplate"> <xsl:with-param name="DebugOpts" select="$DebugOpts"/> </xsl:call-template> </xsl:template> <xsl:template name="childTemplate"> <xsl:param="DebugOpts" select="."/> <xsl:text>The value of $DebugOpts is: </xsl:text> <xsl:value-of select="$DebugOpts"/> </xsl:template> </xsl:stylesheet> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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