RE: [xsl] xslt 2 grouping

["Michael Kay" <michael.h.kay@xxxxxxxxxxxx>]

The XSLT 2.0 solution (untested) is:

<xsl:for-each-group select="e1" group-by=".">
  <e1 name="{.}">
    <xsl:for-each-group select="current-group()" group-by="@att">
      <xsl:value-of select="concat(@att, ' ')"/>
    </xsl:for-each>
  </e1>
</xsl:for-each>

You could also use distinct-values().

I don't understand your comment that you can't use keys because there
are 1200 lines?

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> DPawson@xxxxxxxxxxx
> Sent: 11 July 2002 15:32
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] xslt 2 grouping
> 
> 
> With the following XML I'm trying to group and find uniques
> 
> <p>
> <el att='a'>x</el>
> <el att='b'>x</el>
> <el att='c'>x</el>
> <el att='d'>y</el>
> </p>
> I have about 1200 lines of this, so keys are out.
> 
> I want to find all the el elements with content 'a'
> which have *different* att attribute values,
> 
> to produce
> 
> <el name='x'>a b c </el>
> 
> I.e. list x, together with all the attributes att
> which are different.
> 
> I'm guessing its a good one for xslt 2, for-each and 
> group-by, but I'm stumped on the syntax.
> 
> Any help appreciated,
> DaveP.
> 
> 
> 
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