Subject: Re: [xsl] XPath iteration? From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Fri, 12 Jul 2002 09:25:57 +0100 |
Hi Derek, > I'm sorry if this question is inappropriate here, but I haven't > found a more appropriate place to ask, nor have I found a FAQ that > addresses my question. Don't worry; this is a good place to ask your question. > I'm trying to come up with an XPath expression that will "iterate". > What I have in mind is something to the effect of: > > /Root/SomeNode[position()!=position(/Root/SomeNode)] > > which would compare each SomeNode against all other SomeNode's > except itself (there are multiple SomeNode children of /Root). Given that all the SomeNode elements are siblings of each other, you can collect together the other SomeNodes into a node set with: preceding-sibling::SomeNode | following-sibling::SomeNode I don't know what you want to do with them, though -- perhaps you could describe what you actually want to get from the XPath? Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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