Re: [xsl] math get maximum and subtract 1

["sascha" <sascha@xxxxxxxxxx>]

Hello again,

I tried to get into that , but i don't know how to change the for-each
syntax.
It's a locigal problem....
The loop around the rows is still correct , isnt it? Well at least it
creates the right number of rows.

<xsl:for-each select="DESCRIPTION_ITEM[@col = 0]">
    <fo:table-row>

But this seems to need a correction

     <xsl:for-each select="../DESCRIPTION_ITEM [(position() - 1) mod $nrows
= current()/@row]">

I know, you tried to explain that to me and i understood what you described,
but i don't get how to change it to work with the new input

Could you please just give me another hint?
Any more info needed?

Sascha

----- Original Message -----
From: "Jeni Tennison" <jeni@xxxxxxxxxxxxxxxx>

> Yes; it looks like they're sorting it by row first now, rather than by
> column. That's great, since it still means that the last
> DESCRIPTION_ITEM in the DESCRIPTION_TABLE has the maximum row/col, so
> you can still use:
>
> <xsl:variable name="nrow"
>   select="/DESCRIPTION_TABLE/DESCRIPTION_ITEM[last()]/@row" />
>
> <xsl:variable name="ncol"
>   select="/DESCRIPTION_TABLE/DESCRIPTION_ITEM[last()]/@col" />

...

<xsl:for-each select="DESCRIPTION_ITEM[@col = 0]">
    <fo:table-row>
      <xsl:for-each select="../DESCRIPTION_ITEM [(position() - 1) mod $nrows
= current()/@row]">


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