Re: [xsl] Expression Logic Problem

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

> > > > 1. preceding-sibling:
> > > >
> > > > Instead of <xsl:if test="self::node()[1]"> use <xsl:if
> > > > test="not(preceding-sibling::field/@id = @id)">
> > >
> > > won't this return the very first field in document order?
> >
> >
> > No, it only tests whether there is not a preceding-sibling field 
> > element, which has the same @id like the current one.
> >
> > You can write "not(preceding-sibling::field[@id = current()/@id])" if 
> > you want.
>
>
> It is my understanding that if you have:
>
> <a>
>   <f id="1"/>
>   <f id="2"/>
>   <f id="2"/>
> </a>
>
> and you happen to be on the 3rd f node you would get:
>
> preceding-sibling::field/@id=1
>
> and current()/@id=2
>
> but if you use:
>
> preceding-sibling::field[1]/@id=2
>
> Is this wrong?

It's not soo wrong ;-) All your statements are correct when using 
<xsl:value-of select="..."/>. And they were correct if I had used 
"preceding-sibling::field/@id != @id.

In the example above the node set of all id attributes of all 
preceding-sibling field elements are compared with the node set of the 
id attribute of the current node.

It obtains for the usage of not(): it's true if no value in node set 1 
is equal to a value in node set 2.

While for != : it's true if one value in node set 1 is not equal to the 
values in node set 2.

If I'm wrong or unprecise please correct me.

Regards,

Joerg


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