[xsl] How to test by nodename if node exsits and not empty

[René de Vries <RdVries@xxxxxxxxxxx>]

Hi,

I try to do this: pass a nodename of a childnode of the current node as a
parameter to a template and test if it exists and, if so, if it has a
contents and/or attributes.
My problem is that I can't get the the expression right to count the number
of attributes of $Node. For example count(@*) returns the number of
attributes for the current node and I've tried count($Node/@*),
count($Node[@*]), count($Node/*[@*]) and so on, but the parser complains
that the "expression must evaluate to a node-set".
If I don't count the attributes, <aNode xyz="someinfo"/> would be considered
empty, which I don't want.

WHAT DO I DO WRONG????

my template:
<xsl:template name="TestIfNodeExistsAndIsFilled">
    <xsl:param name="NodeName" select="'NoNodeName'"/>

    <xsl:variable name="Node">
        <xsl:copy-of select="./*[local-name()=$NodeName]"/>
    </xsl:variable>

    <xsl:if test="(not ($Node)) or (string-length(normalize-space($Node))=0
and count(### what expression? ###))">
        <Error>
            <Name><xsl:value-of select="$NodeName"/></Name>
            <Description>
                <xsl:value-of select="$NodeName"/>
                <xsl:choose>
                    <xsl:when test="(not ($Node))">
                        <xsl:text> not present</xsl:text>
                    </xsl:when>
                    <xsl:otherwise>
                        <xsl:text> not filled</xsl:text>
                    </xsl:otherwise>
                </xsl:choose>
            </Description>
        </Error>
    </xsl:if>
</xsl:template>

Greetings René
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