Re: [xsl] transforming XML into XML using XSLT.

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Neel,

At 04:11 PM 8/13/2002, you wrote:
> Is it possible to convert XML[having useful +unnecessary data ]
> -----to-----> XML [having Useful data] using XSLT.Could you please help
> me out with an example.

Sure:

<source>
 <useful>This is an example on XSL-List</useful>
 <unnecessary>It's rather pointed (unnecessarily so).</unnecessary>
</source>

<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<!-- this could be a near-identity transform, but for ease of illustration
     we'll just strip out the node structure instead -->

<xsl:template match="/">
  <result>
    <!-- this template is here so the result is actually XML, rather
         than simply a well-formed external parsed entity -->
    <xsl:apply-templates/>
  </result>
</xsl:template>

<xsl:template match="unnecessary"/>

</xsl:stylesheet>

But I think the real answer depends on what's useful and what's 
unnecessary, and how you tell the difference.

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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