Re: [xsl] document() function

["Thomas B. Passin" <tpassin@xxxxxxxxxxxx>]

[Felmey, Jonathan]

> I am trying to do the following:
> document('file:///c:/servers/mserver/ojamc2vpt1_part.xsd') to open a
> document not in the same directory as my stylesheet. It does not work.
Can
> this be done and if so what is the correct syntax for doing this?
>

If you are trying this from within a browser, security restrictions would
prevent it.  Otherwise, it may be the syntax of the file: URL.  Try some of
the normal variations, like

file:///c:\servers\mserver\ojamc2vpt1_part.xsd
file:c:\servers\mserver\ojamc2vpt1_part.xsd
file:c:/servers/mserver/ojamc2vpt1_part.xsd

There is some ambiguity in the RFC about the exact form of file: URLs,
leading to different interpretions, and different processors can require
different forms.  The form you used works on some processors, but I forget
what works with which.

Cheers,

Tom P


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