Re: [xsl] deep "copy-of" a source fragment

Dave, you rock the house, baby!

I had actually tried the namespace declaration before but I had gotten it wrong.

The HTML Tidy program outputs an [unqualified?] xmlns attribute (declaration) in the <html> root element so the namespace is "html". When I declared this in my the <xsl:stylesheet> root element *as you suggested* then xalan knew what the hell I was refering to by html:body and then behaved as expected.

The source document element looks like this...
<html xmlns="http://www.w3.org/1999/xhtml";>

My stylesheet looks like this:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
    xmlns:html="http://www.w3.org/1999/xhtml";>
    <xsl:template match="/">
        <xsl:copy-of select="/html:html/html:body/node()"/>
    </xsl:template>
</xsl:stylesheet>

I was careful to get an exact match on the URI for the namespace declarations between the source document and the stylesheet. **

QUESTION(S): what is the deal with "where" you declare the namespace? Does it matter? Must I do all my declarations in the root element? If not, must I do all my declarations in the root stylesheet element if I want the XSL processor to match against them?

** My only concern is that if for whatever reason the namespace declaration changes, it will [silently] "break" my XSL templates. So maybe I will take the easy way out and suppress namespace declarations in my xhtml source reducing it to an anonymous well-formed document which is xhtml by convention (rather than validity).

David Carlisle wrote:

match="/html/body/"

probably there are no elements called html or body Tidy probably wrote th eelements in the xhtml namespace. A namespace is part of teh name of an element, so you'll need

match="/h:html/h:body/"
and xmlns:h="http://www.w3.org/1999/xhtml"; to declare the h prefix on
your xsl:stylesheet element.
David
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