Subject: RE: [xsl] insert default node if it doesn't exist From: Jarno.Elovirta@xxxxxxxxx Date: Tue, 10 Sep 2002 09:34:09 +0300 |
Hi, > I've tried with this XSLT. Problem is that since the match > doesn't find <c> for the 2nd both for b and g, I'll get a <c> > for everyone of them. How can this be solved? > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="xml" version="1.0" encoding="UTF-8" > indent="yes"/> > > <xsl:template match="a/*"> > <xsl:copy> > <xsl:apply-templates > select="@*|node()"/> > </xsl:copy> > <xsl:if test="not(../c)"> > <c>0</c> > </xsl:if> > </xsl:template> try <xsl:template match="a[not(c)]"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> <c>0</c> </xsl:copy> </xsl:template> Jarno - In Strict Confidence: Zauberschloss (Mechanical Fairy Tale remix) XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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