Subject: [xsl] following-sibling From: Alia Mikati <Aliam@xxxxxxxxxxxxxxxxxxxx> Date: Tue, 10 Sep 2002 15:49:26 +0300 |
Hello again, I have this part of xml file and I wanna search in a row for the value ': 139597.1' and get its sibling 'Status: RONY'. .... <tr> <td></td> <td colspan="2" nowrap="nowrap"> <small>Type: N3</small> </td> <td nowrap="nowrap"> <small> <a href="/help/usaeng/Search/search.html#file">Doc ID</a> : 139597.1</small> </td> </tr> <tr> <td></td> <td colspan="2" nowrap="nowrap"> <small>Score: 100%</small> </td> <td nowrap="nowrap"> <small>Modified Date: 30-JUN-2002</small> </td> </tr> <tr> <td></td> <td nowrap="nowrap"> <small>Status: RONY</small> </td> <td> <small>Platform: HP 9000 Series HP-UX</small> </td> <td> <small>Product: Oracle Server - Enterprise Edition</small> </td> </tr> ... I'm using this xsl but not working. Plz can u tell me what's wrong? Thx again. ... <xsl:template match="body/center/table/tr/td/table/tr/td/small"> <xsl:if test="contains(., ': 139597.1')"> <b> Tar Status is : </b> <xsl:value-of select="normalize-space(following-sibling::tr [position() = 2]/td/small)"/> </xsl:if> </xsl:template> ... XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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