Subject: [xsl] element with namespace From: "Venkateshwar Bommineni" <vbommineni@xxxxxxxxxx> Date: Mon, 30 Sep 2002 11:38:50 -0400 |
Hi all, I am having a problem while trying to match root element which has namespace declaration. here is the test snippet i am trying .. Input XML is: ------------------------------------------------------- <?xml version="1.0"?> <Test xmlns="http://www.foo.com/namespace/v1" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.foo.com/namespace/v1 C:\schema\definition.xsd"> <People> <Person> <FName>fname1</FName> <LName>lname1</LName> </Person> <Person> <FName>fname3</FName> <LName>lname3</LName> </Person> </People> </Test> Input XSL is: --------------------------------------------------------------- <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <Members> <xsl:apply-templates select="Test/People"/> </Members> </xsl:template> <xsl:template match="People"> <xsl:for-each select="Person"> <Member><xsl:value-of select="concat(substring(LName,1,1),'.',FName)"/></Member> </xsl:for-each> </xsl:template> </xsl:stylesheet> Output of above transformation results: --------------------------------------------------------------- <?xml version="1.0" encoding="UTF-8"?> <Members/> And if remove the namespace declaration from my input xml it works fine. So is that namespace declaration not allowed or is there any magic property i need to set in XSL to ignore namespace declarations? thanks in advance Venkat XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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