Re: [xsl] sorted table elements

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

Hello Saverio,

you are on the right way, but it's a dead-end street ;-)

The problem: While you sort the elements and bring them into a new order, 
following-sibling still uses document order, not the order after the 
sorting. You must store the sorting in a variable:

<xsl:variable name="sortedElements">
    <xsl:for-each select="*">
        <xsl:sort data-type="text" select="name()"/>
        <xsl:copy-of select="."/>
    </xsl:for-each>
</xsl:variable>

But now you have a Result Tree Fragment (RTF) in your variable, no longer a 
node set, on which you can operate. You have to use an extension function zo 
convert it back to a node set. For this you can use EXSLT or vendor specific 
extension functions: http://www.exslt.org/exsl/functions/node-set/index.html.

<xsl:variable name="sortedElementsNodeSet" 
select="exslt:node-set($sortedElements)/*"/>

Now preceding-sibling or following-sibling works correctly:

<xsl:for-each select="$sortedElementsNodeSet[position() mod 4 = 1">
  <tr>
    <xsl:for-each select=".|following-sibling::node()[position() &lt; 4]">
      <td>...</td>
    </xsl:for-each>
  </tr>
</xsl:for-each>

Hope this works, it's untested ;-)

Regards,

Joerg

Saverio Perugini wrote:
> Hello,
>
> I'd like to produce a 4 column HTML table where each <td>
> element is alphabetically sorted from cell 1,1 to cell n,4
> (where n is the required number of rows).
>
> The following is an attempt:
>
> <table>
>    <xsl:for-each select="*[position() mod 4 = 1]">
>       <xsl:sort data-type="text" select="name()"/>
>          <tr>
>             <xsl:for-each select=".|following-sibling::node()[position() &lt; 4]">
>                <td>...</td>
>             </xsl:for-each>
>          </tr>
>    </xsl:for-each>
> </table>
>
> This code only sorts all the *[position() mod 4 = 1] elements.
> Therefore, only column one is sorted, whereas I wanted the entire
> table (an linear list from cell 1,1 to cell n,4 sorted).  Can this be done?
>
> Thank You and Best Regards,
>
> S. Perugini

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