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Subject: RE: [xsl] How a node value of an external xml file? From: Jarno.Elovirta@xxxxxxxxx Date: Fri, 11 Oct 2002 14:03:37 +0300 |
Hi,
> <xsl:template name="Address">
> <Line bold="true" dhigh="false" justify="left">
> <xsl:call-template
> name="Resource"><xsl:with-param
> name="txtNode">AddressTitle</xsl:with-param></xsl:call-template>
> </Line>
> </xsl:template>
>
> <xsl:template name="Resource">
> <xsl:param name="txtNode"/>
> <xsl:param name="txtLang">EN</xsl:param>
> <xsl:value-of select="$resource/$txtNode/$txtLang"/>
> </xsl:template>
Rewrite this bit to
<xsl:template name="Address">
<Line bold="true" dhigh="false" justify="left">
<xsl:call-template name="Resource">
<xsl:with-param name="txtNode" select="'AddressTitle'" />
</xsl:call-template>
</Line>
</xsl:template>
<xsl:template name="Resource">
<xsl:param name="txtNode" />
<xsl:param name="txtLang" select="'EN'" />
<xsl:value-of select="$resource/*[local-name() = $txtNode]/*[local-name() = $txtLang]" />
</xsl:template>
Cheers,
Jarno - Suicide Commando: Hellraiser (VNV Nation remix)
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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