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Subject: Re: [xsl] Replace character with line brake in long string From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Fri, 11 Oct 2002 14:26:24 +0100 |
Hi Jussi,
> I have an xml file including the following elements (string can be
> even longer):
>
> <attribute>
> <name>Ranges</name>
> <string>Amplifier IC|Analog Switch|Mixer IC|Modulator IC|Negative Voltage Regulator|Other Analog IC|Phase Locked Loop|Positive Voltage Regulator|Switching PSU Controller IC</string>
> </attribute>
>
> What I would like to get with xsl is
>
> <tr>
> <td>
> Amplifier IC<br/>
> Analog Switch<br/>
> Mixer IC<br/>
> Modulator IC<br/>
> Negative Voltage Regulator<br/>
> Other Analog IC<br/>
> Phase Locked Loop<br/>
> Positive Voltage Regulator<br/>
> Switching PSU Controller IC<br/>
> </td>
> </tr>
There are a couple of approaches. One is to use an extension
str:tokenize() function to tokenise your string and then use
xsl:for-each to iterate over the results. Another is to use a
recursive template to walk through the string with substring-before()
and substring-after() to replace the |s with <br />s. For example:
<xsl:template name="replace">
<xsl:param name="string" select="." />
<xsl:choose>
<xsl:when test="not($string)" />
<xsl:when test="contains($string, '|')">
<xsl:value-of select="substring-before($string, '|')" />
<br />
<xsl:call-template name="replace">
<xsl:with-param name="string"
select="substring-after($string, '|')" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string" />
<br />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
You could call this template from a template matching the string
element as follows:
<xsl:template match="string">
<tr>
<td>
<xsl:call-template name="replace" />
</td>
</tr>
</xsl:template>
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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