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Subject: RE: [xsl] accessing URL parameters from XSL From: Paul Zwarts <Paul.Zwarts@xxxxxxxxxxx> Date: Mon, 4 Nov 2002 13:13:03 +0100 |
Victor,
If you are using ASP, you can capture the request variable and pass it into
the ms-xml parser in such way:
Set XMLSource = Server.CreateObject("MSXML2.DOMDocument.4.0")
XMLSource.Load (lStrRootDir & "\data\directory.xml")
Dim XSLTSource
Set XSLTSource =
Server.CreateObject("MSXML2.FreeThreadedDOMDocument.4.0")
XSLTSource.Load (lStrRootDir & "\directory.xsl")
Dim Transform
Set Transform = Server.CreateObject("MSXML2.XslTemplate.4.0")
Set Transform.Stylesheet = XSLTSource
Dim XMLProcessor
Set XMLProcessor = Transform.CreateProcessor
XMLProcessor.Input = XMLSource
>> XMLProcessor.AddParameter "CurrentUser", requet("<YourVarNameHere>")
Call XMLProcessor.Transform
lObjStrOutput = XMLProcessor.Output
Paz
-----Original Message-----
From: Viktor [mailto:viktoras@xxxxxx]
Sent: maandag 4 november 2002 13:36
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] accessing URL parameters from XSL
Hello all,
I'm having problem with accessing URL parameters from XSL. How can I solve
this problem?
I'm using server-side Microsoft MSXML parser.
Viktor.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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