Subject: Re: [xsl] xslt replace special characters From: "Alice Fan" <arisuu@xxxxxxxxxxx> Date: Fri, 08 Nov 2002 12:14:37 -0800 |
thanks al
From: Greg Faron <gfaron@xxxxxxxxxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] xslt replace special characters Date: Fri, 08 Nov 2002 12:51:21 -0700
At 12:40 PM 11/8/2002, you wrote:How do you replace characters in xslt.
i have a url string that may contain '?' , '&', and '=' i want to convert
? to %3f = to %3d & to %26
is there a good way to do this? i try using translate function but it doesn't work that well. i've also tried writing a recursive template that checks for all occurence of these characters and it doesnt seem to work.
any idea?
<xsl:template name="replace">
<xsl:param name="string" select="''"/>
<xsl:param name="pattern" select="''"/>
<xsl:param name="replacement" select="''"/>
<xsl:choose>
<xsl:when test="$pattern != '' and $string != '' and contains($string, $pattern)">
<xsl:value-of select="substring-before($string, $pattern)"/>
<!--
Use "xsl:copy-of" instead of "xsl:value-of" so that users
may substitute nodes as well as strings for $replacement.
-->
<xsl:copy-of select="$replacement"/>
<xsl:call-template name="replace">
<xsl:with-param name="string" select="substring-after($string, $pattern)"/>
<xsl:with-param name="pattern" select="$pattern"/>
<xsl:with-param name="replacement" select="$replacement"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Greg Faron Integre Technical Publishing Co.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
.......................................................... Email: arisuu@xxxxxxxxxxx Cell: (650) 483-8164 Work: (212) 201-0881 ..........................................................nk
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