[xsl] Generic XSLT Sorting Template

Subject: [xsl] Generic XSLT Sorting Template
From: "MoMad" <momad_no@xxxxxxxxxxx>
Date: Fri, 15 Nov 2002 18:59:07 -0800
I am trying to find a way to create a generic xsl sorting function that
takes 5 parameters, which are the names of the nodes to sort.

I dont understand how to pass parameters to an xsl stylesheet, but basically
i just want a simple sorting function that sorts the xml and returns a
sorted version of the xml using xsl:copy.

So far this is what i got:


<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >

 <xsl:template name="GenericSort">
    <!-- The sort fields -->
    <xsl:param name="SortField0" select="" />
    <xsl:param name="SortField1" select="" />
    <xsl:param name="SortField2" select="" />
    <xsl:param name="SortField3" select="" />
    <xsl:param name="SortField4" select="" />

    <xsl:copy >
      <xsl:apply-templates>
        <xsl:sort select="$SortField0" />
        <xsl:sort select="$SortField1" />
        <xsl:sort select="$SortField2" />
        <xsl:sort select="$SortField3" />
        <xsl:sort select="$SortField4" />
      </xsl:apply-templates>
    </xsl:copy>
 </xsl:template>

</xsl:stylesheet>


But my problem is, it doesnt work... i want the first sort field
(sortfield0) to sort on the global node-set (ancestor::*[next-sibling()]) ??

Any help will be appreciated, thanks
MoMad

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread