Subject: [xsl] Generic XSLT Sorting Template From: "MoMad" <momad_no@xxxxxxxxxxx> Date: Fri, 15 Nov 2002 18:59:07 -0800 |
I am trying to find a way to create a generic xsl sorting function that takes 5 parameters, which are the names of the nodes to sort. I dont understand how to pass parameters to an xsl stylesheet, but basically i just want a simple sorting function that sorts the xml and returns a sorted version of the xml using xsl:copy. So far this is what i got: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template name="GenericSort"> <!-- The sort fields --> <xsl:param name="SortField0" select="" /> <xsl:param name="SortField1" select="" /> <xsl:param name="SortField2" select="" /> <xsl:param name="SortField3" select="" /> <xsl:param name="SortField4" select="" /> <xsl:copy > <xsl:apply-templates> <xsl:sort select="$SortField0" /> <xsl:sort select="$SortField1" /> <xsl:sort select="$SortField2" /> <xsl:sort select="$SortField3" /> <xsl:sort select="$SortField4" /> </xsl:apply-templates> </xsl:copy> </xsl:template> </xsl:stylesheet> But my problem is, it doesnt work... i want the first sort field (sortfield0) to sort on the global node-set (ancestor::*[next-sibling()]) ?? Any help will be appreciated, thanks MoMad XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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