Subject: [xsl] XPATH or 2 templates ? From: Delaney Robin <Robin.Delaney@xxxxxxx> Date: Mon, 18 Nov 2002 13:21:37 +0100 |
This is driding me nuts. If anyone can help I'd appreciate The only node-name I know exists is <Concat>. If I template-match on <Concat> then I get the correct text for the 1st part and not for the 2nd although it's close If I template-match on <Concat/*> then I get the correct text for the 2nd part but not for the first ! Why can I not have template match on <Concat> and <Concat/*> within the same stylesheet ? XML <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="E:\Zvxml\XtraTest\Test.xsl"?> <Concat> <Zula> <Ver>101</Ver> <Mandant> <Anbiete>0204268270</Anbiete> <Adresse> <Strasse>Versicherungsstr. 1</Strasse> <Ort>Offenburg</Ort> </Adresse> </Mandant> </Zula> <Zula> <Ver>202</Ver> <Mandant> <Anbiete>0204268270</Anbiete> <Adresse> <Strasse>Versicherungsstr. 1</Strasse> <Ort>Offenburg</Ort> </Adresse> </Mandant> </Zula> </Concat> XSL <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text"/> <xsl:template match="Concat"> <xsl:for-each select="*[1]//*[not(*)]"> --> 1st part <xsl:value-of select="local-name()"/> <xsl:if test="position()!=last()">;</xsl:if> </xsl:for-each> <xsl:text> </xsl:text> <xsl:for-each select="//*[not(*)]"> <xsl:value-of select="node()"/> --> 2nd Part <xsl:if test="position()!=last()">;</xsl:if> </xsl:for-each> <xsl:text> </xsl:text> </xsl:template> </xsl:stylesheet> Output: Ver;Anbiete;Strasse;Ort 101;0204268270;Versicherungsstr. 1;Offenburg;202;0568324;Bahnhofstr. 1;Offenburg I Need: Ver;Anbiete;Strasse;Ort 101;0204268270;Versicherungsstr. 1;Offenburg 202;0204268270;Versicherungsstr. 1;Offenburg XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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