Subject: Re: [xsl] Accessing the source nodetree while in another context From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Wed, 20 Nov 2002 17:18:01 +0100 |
Hi All,
Can anyone tell me if there is a way to access the source nodetree while within another nodetree context? Here's a simple example -
... <xsl:variable name="mydoc" select="document('mydoc.xml')"/> <xsl:apply-templates select="$mydoc//*"/> ...
While the apply-templates is run, the context for the current node is set to $mydoc and any templates that are executed use that. If I want to access the nodetree for the source document on which the transform was run, is there a simple syntax to specify it? I see how I could do this if I used an xsl:for as I could copy part of the source nodetree into a variable and just access the variable, but it seems like if I want to use templates, they are going to be in a global scope and I won't be able to access my variable as it isn't in the same scope. Therefore, I would need some syntax to specify the source nodetree directly.
Thanks for any and all comments. Please let me know if I'm missing something simple :-). Jeff Rosler
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Accessing the source nodetree, Jeff Rosler | Thread | Re: [xsl] Accessing the source node, David Carlisle |
Re: [xsl] Differents between XML-Fi, Brian Grainger | Date | Re: [xsl] Accessing the source node, David Carlisle |
Month |