Subject: Re: [xsl] Selecting multi-existant elements only once From: Sorin Marti <mas@xxxxxxxxxx> Date: Thu, 28 Nov 2002 15:27:37 +0100 |
Or you could use xsl:key, which is quicker and very useful.
Thanks, I changed my code. mas
-----Original Message----- From: Sorin Marti [mailto:mas@xxxxxxxxxx] Sent: 25 November 2002 15:30 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Selecting multi-existant elements only once
I've got the solution...sorry for asking...
<xsl:for-each select="//departement/profession[not(desc=preceding::desc)]">
<xsl:value-of select="desc"/>
</xsl:for-each>
Sorin Marti
I wrote:
Hi all,professions.
I've got a XML-File with following structure. There are different departements and in each departement there are different
I want to have every profession of all departement once...If there is
a Manager in departement a and departement b, "Manager"should only be
printed out once...
How can I do that?
[...] <departement> <profession> <desc>Manager</desc> <salary>5000</salary> </profession>
<profession> <desc>Assistant</desc> <salary>3000</salary> </profession>
<profession> <desc>Employee</desc> <salary>2000</salary> </profession> </departement>
<departement> <profession> <desc>Manager</desc> <salary>5000</salary> </profession>
<profession> <desc>Worker</desc> <salary>2000</salary> </profession> </departement>
[...]
Thanks for your help !
Sorin
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