Re: [xsl] Testing the name of parent node

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

Hello Ragulf,

Ragulf Pickaxe wrote:
> Hello all,
>
> I think this is trivial, but I can't seem to find how to do it:
>
> I am in a node <a...> which can have any number of parents or childs of 
> the same type. I want to know if the node I have in hand is the topmost 
> <a...>.

the solution:

<xsl:if test="not(ancestor::a)">
  no a above me in the tree
</xsl:if>

<xsl:if test="not(ancestor::*[name() = 'a'])">
  the same here
</xsl:if>

> I tried looking at the name() funktion, but the explanation was not very 
> clear to me (Michael Kay's book, 2nd edition), and I don't know if this 
> is the right track at all.

the explanation:

name() returns the complete name of an element. So a <a/> in input 
returns the string 'a', <html:a/> returns 'html:a' and so on.

> I really would appreciate some pointers.
>
> Thank you
> Ragulf Pickaxe :)

Regards,

Joerg


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