Re: [xsl] how to match attributes in templates?

[Francis Norton <francis@xxxxxxxxxxx>]

Hi Alice,

Alice Fan wrote:

> this is what i'm doing to copy all nodes except for a specific element 
> name.  how do i specify a specific attribute inthe if statement?

Well, you can find an example of how to copy all nodes in the XSLT spec 
(in the identity transform described at 
http://www.w3.org/TR/xslt#copying) and you can build on this to match 
and trap a specific attribute (or element)

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

 <!-- copy all nodes... -->
 <xsl:template match="@*|node()">
   <xsl:copy>
     <xsl:apply-templates select="@*|node()"/>
   </xsl:copy>
 </xsl:template>

 <!-- ...except this one -->
 <xsl:template match="@id" />

</xsl:stylesheet>

This is somewhat similar to what you were trying to do, but matching 
templates by pattern is more fun (and more in the spirit of XSLT) than 
coding xsl:if statements.

But if you do want to use explicit logic rather than pattern matching, 
you can use:

   <xsl:if test="not(self::someelement)">...</xsl:if>

if you know the element name at build time, or use:

   <xsl:if test="not(localname() = $targetNodeName)">...</xsl:if>

if the element name will be set at run time.

Francis.





XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list