[xsl] 10 records per page

Subject: [xsl] 10 records per page
From: "Mandeep S Dhadda" <m.s.dhadda@xxxxxxxxxxx>
Date: Mon, 3 Feb 2003 09:58:50 -0000
Hello,

I have common question. The question is how to show 10 records at a time and
also show navigation links i.e page1 page2 which  will show the other
records. I have checked the example at
http://www.dpawson.co.uk/xsl/sect2/sect21.html but can't see how it make it
work in mine. I am very new to xsl!

This is mine: (It shows the first 10 records)!

	  <xsl:for-each select="feedbackDetailsTag[position() mod 10 = 1]">
							<tr>

								<td width="11%" height="18" bgcolor="#FFFFFF" class="bold">
									<p>
										<a>
											<xsl:attribute name="href">
												<xsl:value-of
select="$Portal.Servlet.Normal"/>GI_ID=<xsl:value-of
select="../../../@id"/>&amp;read_feedback=true&amp;feedback_id=<xsl:value-of
select="feedbackIdTag"/></xsl:attribute>
											<xsl:value-of select="userNameTag"/>
										</a>
									</p>
								</td>
								<td colspan="3" bgcolor="#FFFFFF">
									<p>
										<xsl:value-of select="feedbackDateTag"/>
									</p>
								</td>
								<td width="29%" bgcolor="#FFFFFF">
									<p>
										<xsl:value-of select="messageCategoryTag"/>
									</p>
								</td>
								<td width="34%" bgcolor="#FFFFFF">
									<p>
										<xsl:value-of select="requireFeedbackTag"/>
									</p>
								</td>
							</tr>


						</xsl:for-each>

Thanks

Mandeep


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