RE: [xsl] Newby Question reformatting xml

[cknell@xxxxxxxxxx]

> -----Original Message-----
> From:     "Michael A. Thompson" <mathomp@xxxxxxxxxxxxxx>
>
> <xsl:template match="BBB">
>   <xsl:element name="BBB">
>     <xsl:attribute name="num">
>       <xsl:value-of select="//DDD/@id">
>       </xsl:value-of>
>     </xsl:attribute>
>     <xsl:value-of select="."></xsl:value-of></xsl:element>
> </xsl:template>

Your problem is with the XPath expression "//DDD/@id". It selects the first node that matches this pattern, which, of course, is only correct for the children of the first <DDD> element. Use this expression instead:

"parent::node()/attribute::id"

or in abbreviated format:

"../@id"

While the latter is more concise, the former is easier to understand. Both expressions evaluate identically.

If you are going for brevity, you could re-write the template so:

<xsl:template match="BBB">
  <xsl:element name="BBB">
    <xsl:attribute name="num"><xsl:value-of select="../@id" /></xsl:attribute>
    <xsl:value-of select="." />
  </xsl:element>
</xsl:template>


--
Charles Knell
cknell@xxxxxxxxxx - email



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