| Subject: AW: [xsl] Getting the value of the tag itself. From: Delaney Robin <Robin.Delaney@xxxxxxx> Date: Thu, 20 Mar 2003 16:30:27 +0100 | 
<xsl:value-of select="name()"/>	
- Robin
                                                     
Robin Delaney
FJA Feilmeier & Junker GmbH    
Elsenheimerstraße 65,	80687 München.
*   +49 (0) 89 - 76 901-7058
Fax   +49 (0) 89 - 76 901-9502
web  http://www.fja.com
*    Mailto:Robin.Delaney@xxxxxxx	
> -----Ursprüngliche Nachricht-----
> Von:	Simon Kelly [SMTP:kelly@xxxxxxxxxx]
> Gesendet am:	Donnerstag, 20. März 2003 16:08
> An:	xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff:	[xsl] Getting the value of the tag itself.
> 
> Hi all,
> 
> I know haow to get all the relevent information from a node, but I am
> struggling to remeber how to get the nodes name itself.  IE if I have a
> node
> called <table name="table1"> how do I print out it's name table, and not
> the
> @name table1??
> 
> Cheers
> 
> Simon
> 
> 
> 
> Institut fuer
> Prozessdatenverarbeitung
> und Elektronik,
> Forschungszentrum Karlsruhe GmbH,
> Postfach 3640,
> D-76021 Karlsruhe,
> Germany.
> 
> Tel: (+49)/7247 82-4042
> E-mail : kelly@xxxxxxxxxx
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
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