Re: [xsl] Breaking up XML(XHTML) into pages

["Leonidas Kanellos" <leonidaskanellos@xxxxxxxxxxx>]

Hi David,

Thanks for the reply.

I put //div[@class='section'][popsition()=1]//h2 in XPath and it is true. It 
gives the first h2 section.

I change <xsl:param name="page_number" select=" '5' "/>

to <xsl:param name="page_number" select=" 5 "/> but i cannot get the section 
that i want its time. In this case, the fifth h2 section.
I get all the text instead.

Do you think that the problem exist in this code:

<!-- manage h2 elements -->
<xsl:template match="//xhtml:div[@class='section']/xhtml:h2">

I use condition in order not to have the external (<a>) h2 at the output
<xsl:choose>
<xsl:when test="./xhtml:a">
</xsl:when>
<xsl:otherwise>

Here i try to insert the parameter.
Maybe it would be better to have an if condition here but i must have the 
choose condition as well for the external links.

<input name="page_number" value="{$page_number}"/>
<xsl:value-of select="*">
</xsl:value-of>
<xsl:apply-templates/>

I give an id to all the h2 in order to link to them externaly or internaly.

<h2 class="section" id="{generate-id()}">
<a name="{generate-id()}">
<xsl:value-of select="."/>
</a>
</h2>

</xsl:choose>
</xsl:template>


At the output for example, i get for the third h2 section this:
<input xmlns="" name="page_number" value="" />Enquiries<h2 xmlns="" 
class="section" id="h243592048">

But i don't know how i will pick it up at the url.


I hope i explained my problem well cause i am confused as well:)

Regards

Leo



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