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RE: [xsl] transforming to breaks

Subject: RE: [xsl] transforming to breaks
From: Jarno.Elovirta@xxxxxxxxx
Date: Tue, 25 Mar 2003 17:34:04 +0200
> I have a node like <nodeName>blah blah&#13;&#10;more blah 
> blah</nodeName>.
> I wish to transform this to html, using <BR></BR> for the carriage
> return/linefeed combo.
> 
> How can I do this?

Recursive template, e.g.

template "changer"
  param "text"
  choose
    when contains($text, "&#xA;")
      value-of substring-before($text, "&#xA;")
      <BR></BR>
      call-template "changer>
        with-param "text" substring-after($text, "&#xA;")
    otherwise
      value-of $text

The XML parser changes &#13;&#10; sequences into single &#10;, so you just need to change LINE FEED characters.

Cheers,

Jarno - Linnunradan käsikirja liftareille: Osa 14

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
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