RE: [xsl] xpath question

["Andrew Welch" <AWelch@xxxxxxxxxxxxxxx>]

> how could i get the matching description for every column,
> when i loop though them via the order described in the order
> node?

Hi,

You would need to count the preceding-siblings (and itself) of the current <column> element, and then apply-templates to the corresponding <description> element, something like:

<xsl:apply-templates select="/root/descriptions/description
                             [position() = 
                             count(current()/preceding-sibling::column|.)]"/>

But to be honest thats really awful xml - if you are able to change it I would do that first.

cheers
andrew

 

> hi!
> 
> i would have an additional question to this:
> 
> if my document would look like this:
> 
> <root>
>    <descriptions>
>      <description>this is an apple</description>
>      <description>this is an orange</description>
>    </descriptions>
>    <group>
>       <apple>bla</apple>
>       <orange>bla</orange>
>    </group>
>    <group>
>       <apple>bla</apple>
>       <orange>bla</orange>
>    </group>
>    <order>
>      <column name="orange" />
>      <column name="apple" />
>    </order>
> </root>
> 
> 
> how could i get the matching description for every column,
> when i loop though them via the order described in the order
> node?
> 
> somehow i cannot think of a way to do that with xpath : /
> 
> thanks!
> 
> ciao!
> florian
> 
> 
> 
> > At 12:07 PM 3/27/2003, you wrote:
> > >i have a document xml doc like this:
> > >
> > ><root>
> > >   <group>
> > >      <apple>bla</apple>
> > >      <orange>bla</orange>
> > >   </group>
> > >   <group>
> > >      <apple>bla</apple>
> > >      <orange>bla</orange>
> > >   </group>
> > >
> > >   <order>
> > >     <column name="orange" />
> > >     <column name="apple" />
> > >   </order>
> > ></root>
> > >
> > >i would like to do the following: im going though all the 
> column nodes
> > >and would like to access the group nodes where the column 
> attribute name
> > >and the group node name match up.
> > >
> > >basically i can just not think of a way to do that in 
> xpath.. anybody
> > >got an tip? how can i say in xpath that it should get the node with
> > >the name in @name and not just access the name attribute of a group
> > >node..
> > 
> > 
> > 
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