Re: [xsl] Empty spaces turn to %20

[Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>]

Hi Brian,

> This will get easier in XSLT 2.0, right?  Something like:
>
> <xsl:analyze-string select="text()" regex="%20">
>   <xsl:non-matching-substring>
>     <xsl:value-of select="."/>
>   </xsl:non-matching-substring>
>   <xsl:matching-substring>
>     <xsl:text> </xsl:text>
>   <xsl:matching-substring>
> </xsl:analyze-string>
>
> A bit unwieldy for a string replacement construct (unless I'm
> missing a shorthand way of doing this), but I'll take it,
> particularly when I have no control over the source XML.

Easier would be to use the replace() function in XPath 2.0:

  <xsl:value-of select="replace(text(), '%20', ' ')" />

You only need to use <xsl:analyze-string> if you want to do further
manipulation of the matching (or non-matching) strings.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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