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Subject: Re: [xsl] generate full xpath name to an attribute? From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 31 Mar 2003 16:23:16 +0100 |
yikes! - looks like the simplest way is to have:
<xsl:template match="name">
<xsl:for-each select="ancestor-of-self::*">
<xsl:value-of select="name()" /><xsl:text>/</xsl:text>
</xsl:for-each>
<xsl:value-of select="." />
</xsl:template>
depending on your document type this might not give you an unambigous
path back to your attribute (and you probably want a @ before that last
step)
eg
<x>
<a id="a1"/>
<a id="a2"/>
</x>
both id attributes would get a path of /x/a/id from the above code.
David
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