Subject: RE: [xsl] transforming a stylesheet that has imports and includes From: Américo Albuquerque <aalbuquerque@xxxxxxxxxxxxxxxx> Date: Fri, 4 Apr 2003 18:23:12 +0100 |
Hi > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Andrew Welch > Sent: Friday, April 04, 2003 10:20 AM > To: Xsl-List (E-mail) > Subject: [xsl] transforming a stylesheet that has imports and includes > > > > hi all, > > I need to do an indentity transform on a stylesheet that has > imports and includes - but as the stylesheet is treated as > xml the imports/includes wont be performed. How can I get > the full stylesheet and then transform that? (Im using trax) > You only need to do something like: <xsl:template match="xsl:import|xsl:include"> <xsl:apply-templates select="document(@href)/xsl:stylesheet/node()"/> </xsl:template> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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