Re: [xsl] xsl:if giving me "Invalid type" error

Subject: Re: [xsl] xsl:if giving me "Invalid type" error
From: "James J. Ramsey" <jjramsey_6x9eq42@xxxxxxxxx>
Date: Tue, 15 Apr 2003 11:56:12 -0700 (PDT)
--- Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> wrote:
> James,
> 
> How have you declared $firstDiv?

It is a string. :(

I declared it like this.

<xsl:variable name="firstDiv">
          <xsl:choose>
            <xsl:when
test="div[1]|div0[1]|div1[1]|divGen[1]">
              <xsl:for-each
select="div[1]|div0[1]|div1[1]|divGen[1]">
                <xsl:if test="position()=1">
                  <xsl:value-of select="name()"/>
                </xsl:if>
              </xsl:for-each>
            </xsl:when>
            <xsl:otherwise>
              <xsl:value-of select="''"/>
            </xsl:otherwise>
          </xsl:choose>
        </xsl:variable>

I was trying to store the name of whatever the first
top-level <div*> was. Maybe

<xsl:variable name="firstDiv">
  <xsl copy-of
select="(div[1]|div0[1]|div1[1]|divGen[1])[1]"/>
</xsl:variable>

would work better for what I need to do (which is to
keep track of that first top-level <div*>)?


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