Subject: Re: [xsl] xsl:if giving me "Invalid type" error From: "James J. Ramsey" <jjramsey_6x9eq42@xxxxxxxxx> Date: Tue, 15 Apr 2003 11:56:12 -0700 (PDT) |
--- Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> wrote: > James, > > How have you declared $firstDiv? It is a string. :( I declared it like this. <xsl:variable name="firstDiv"> <xsl:choose> <xsl:when test="div[1]|div0[1]|div1[1]|divGen[1]"> <xsl:for-each select="div[1]|div0[1]|div1[1]|divGen[1]"> <xsl:if test="position()=1"> <xsl:value-of select="name()"/> </xsl:if> </xsl:for-each> </xsl:when> <xsl:otherwise> <xsl:value-of select="''"/> </xsl:otherwise> </xsl:choose> </xsl:variable> I was trying to store the name of whatever the first top-level <div*> was. Maybe <xsl:variable name="firstDiv"> <xsl copy-of select="(div[1]|div0[1]|div1[1]|divGen[1])[1]"/> </xsl:variable> would work better for what I need to do (which is to keep track of that first top-level <div*>)? __________________________________________________ Do you Yahoo!? The New Yahoo! Search - Faster. Easier. Bingo http://search.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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